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x^2+35x+285=0
a = 1; b = 35; c = +285;
Δ = b2-4ac
Δ = 352-4·1·285
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{85}}{2*1}=\frac{-35-\sqrt{85}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{85}}{2*1}=\frac{-35+\sqrt{85}}{2} $
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